**Question:**how do u solve this?theres websites that say how to do it but i still dont understand

**Answers:**

(the short way)

180/3 = 60

so

60 + 60 + 60 = 180

then take 2 from the first and add 2 to the third gives

58 + 60 + 62 = 180

(the long way)

algebraically you need to find x,y,z such that

x + y + z = 180

since they are consecutive evens

y = x+2

and

z = y+2

= (x+2) +2 = x+4

so

180 = x+y+z = x+(x+2)+(x+4) = 3x +6

solving gives

x=58

so

y = x+2 = 60

and

z = x+4 = 62

∴ 58 + 60 + 62 = 180 as above

.

Consider the minimum even number is x. then the next even number will be x+2 and the third will be x+4. As per your question, all these three should add upto 180. So, write the following statement

x(min. number)+(x+2)+(x+4)=180

i.e. 3x+6=180

3x=180-6=174

x=174/3=58.

Now, x is the min. even number which is 58, so x+2 will be 60 and x+4 will be 62.

Bible and VD did it way more complicated than I did. I figured it had to group around 60 and came up with

58, 60 and 62.

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