PV = nRT, d = m / V, V = m / d
Pm / d = nRT, for a 100 g sample of the gaseous mixture
[(435 / 760)*100] / 1.104 = n*( 0.08206)*(300)
n = 2.11 moles of mixture
O2 + Kr ----> 2.11 moles mixture
[32.0g O2 / 115.8g mixture]*100 = 27.6% O2 composition per mole of mixture
(2.11 moles mixture)*(.276) = .583 moles O2
actually...i'm just gonna stop here because I don't know what i'm doing anymore haha
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