ters in 5 hours.How much of his trip was over hills?
let's say the time he walks 3 km/h is called t1
and the time he walks 4 km/h is called t2
t1 + t2 = 5
3×t1 + 4×t2 = 18
if t1 + t2 = 5 then t2 = 5 - t1
3×t1 + 4× (5-t1) = 18
3×t1 + 20 - 4×t1 =18
20 - t1 = 18
t1 = 2 hours
which is the time he walks 3 km/h
and t2 = 3 hours
now lets test
(3 × 2) + (4 × 3) = 6 + 12 = 18
so there you have it.
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