**Question:**Alisha ran a total of 32 miles during three days of training for a marathon. On the second day of her training session, she ran 6 miles less than on the first day and 2 miles less than on the third day. How many miles did she run on the first day?

Can someone please help me with this? I just went back to school and my brain isn't functioning correctly.

lol, thank you! :-)

**Answers:**

Let x equal the number of miles she ran the 1st day.

Let (x - 6) equal the number of miles she ran the 2nd day.

Let (x + 2) equal the number of miles she ran the 3rd day.

Solve for x:

x + (x - 6) + (x + 2) = 32

3x - 4 = 32

3x = 36

x = 12 miles

She ran:

12 miles the first day.

6 miles the second day.

14 miles the third day.

** Always check your work **

12 + 6 + 14 = 32 miles.

Good luck in your studies,

~ Mitch ~

Edit:

I corrected my error, as I had misread the question.

Seems like my brain isn't functioning correctly either ^-^.

day one=a day 2 =b day 3 = c

b-6=a

b-2=c

32-6-2=24

24/3=8

8+6=14=a

8+2=10=c

x stands for second day

(6+x) + x + (2 + x) = 32

since she ran 6 less than first day on her second day, it is the same as running six more on first day than second day..same with the third day

solve the rest yourself

I am pretty sure Mitch's answer is wrong

she ran 14 miles, lol sry i was born a little slow 0.o

EDIT: Sorry to say mitch, but .33 + .33 + .33 is equal to .99 0.o

x+x+6+x+2=32

3x+8=32

3x=24

x=8

She ran 14 miles on the first day, 8 on the second day, and 10 on the third day.

X is the miles run on the first day

X-6 is the miles run on the second day (this is straight from the problem)

X-4 is the miles run on the third day (If she ran 2 miles less on the second day than the third, she ran 4 miles less on this day than the first)

Lets add up the miles

X + (X-6) + (X-4) = 32 ==>

3X - 10 = 32 ==>

3X = 42

X = 14

Alisha ran 14 miles on the first day.

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