A=6 b=3 c=5 how do i find sin A?? :[[[[[[[[?



Answers:
sinA=(b^2+c^2-2*a^2)/2*bc
=(3^2+5^2-2*6^2)/2*5*3
=(9+25-72)/30
=-34/30
=-17/15

i think it's correct. it's not a right angle. so you should used this formula:
sinA=(b^2+c^2-2*a^2)/2*bc
Sin A = 3/6 = 1/2 = Sin 30
get a good calculator and type in sin 6
is that a trick question

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