cant answer that questions enless you have the height that it is falling.
but you use cross multiplying. i just did something like that in math but i had the distance to cause without it you cant really get an answer.
give me the points
Sorry, this problem cannot be solved as is. We will need the amount of time the object fell to determine how far it goes 23m/s.
Vf^2 = 2ad + Vi^2
Vf = final velocity (23 m/s)
a = acceleration (9.8 m/s^2)
d = displacement or change in positions (23m)
Vi = initial velocity (0m/s)
23^2 = 2(9.8)d + 0^2
529 = 19.6d
d =~ 26.99m
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