# Solve for P: 7 – sqrt(P+3) = 5?

7-5=sqrt(P+3)
2=sqrt(P+3)
squaring both sides of the equation: 2^2 =P+3
4=P+3
4-3=P
1=P
First, add the sqrt part to both sides and subtract 5 from both sides to get 2 = sqrt(P+3)

Then square both sides which cancels out the sqrt on the right, and makes the 2 become 4: 4 = P+3

Then subtract 3 from both sides and you have it.
7-sqrt(p+3)=5
so -sqrt(p+3)=5-7
-sqrt(p+3)=-2
If you divide by -1 then
sqrt(p+3)=2
then square both sides.
p+3=4 then
p=1
7 - sqrt(P+3)=5
- sqrt(P+3)= -2 x -1
(sqrt(P+3))^2=2^2
P+3=4
P=4-3
P=1

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