# (2n-3+n)/2=3?

Question:please show me how you did it.

Are you looking for the value of n?

2n-3+n/2=3

after multiplying both sides by 2, the equation will look

2n-3+n=6

3n-3=6

3n=9

divide both sides by 3

n=3
In the parenthesis you can simplify to:

(3n-3)/2=3

Multiply both sides by 2

3n-3=6

3n=9

Divide both sides by 3

n=3
first you change the "/2" from side which should now multiply... (2n-3+n)=3*2
Remove the parenthesis now and multiply... 2n-3+n=6
Now change the -3, it will add now... 2n+n=6+3
Do the math... 3n=9
Now move the 3, it is multiplying so no it will divide... n=9/3
and done ... n=3
lets check... (2(3)-3+(3))/2=3
All you would do is multiply both sides by 2 to get rid of the divided by two. That would leave you with 2n-3+n=6. You would then add the n's together to get 3n-3=6. Then you add 3 to both sides to cancel the minus three. That leaves you with 3n=9 which means that n=3.
Ur question is (2n - 3 +n) / 2=3,right
OK so u need to cross multiply the denominator of LHS with the numerator of RHS,like this
2n-3+n=2 x 3
Then do the following :-
2n - 3 +n=6
Then collect the like terms
2n +n=6+3
3n=9
Then divide by bringing 3 on RHS side
n=9/3
n=3
if u liked my procedure ,plzzzz choose my answer to be the best answer.

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