A Ball is thrown upward from a height of 15 Feet with an initial upward velocity of 5 ft/s.?

Question:A Ball is thrown upward from a height of 15 Feet with an initial upward velocity of 5 ft/s. Use the formula h=-16t^2+vt+s to find out how long it will take for the ball to hit the ground?

Answers:
the general formula is:

y(t) = 1/2at^2 + V(0)t + y(0) (a is constant and it's equal to g=9.81 m/(s^2) as it's a free fall)

but with the formula you gave what is s?? if we consider the units, s must be a height. I'll suppose that it's the initial height (15ft).

we're looking for t when h=0

h = -16t^2 + v(0)t + s
0 = -16t^2 + 5t + 15

using quadratic formulas, you can find 2 values of t, but just 1 positive value. as time cannot be negative, the positive value is the correct one, and it's the one found by calculating (i cant put square root so i'll put sr):
(-5 - sr(25-4*(-16)*15))/(2*-16) = mmmMMMMMMM u can do it...

it's almost T = 1.125s
Respect Beer.
plug in 5 for v and 15 for h
then solve for t
H= -16t^2 + 5t + 15
if you think about it, H = y and t = x
it's a simple quadratic graphing problem
Your answer is:
T = 1.137 seconds about.

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